Math, asked by ashwaniprakash, 11 months ago

Find the value(s) of k for which the quadratic equation x² + 2v2kx + 18 = 0 has equal
roots​

Answers

Answered by riyaraj91
1

b^2-4ac=0

4v^4k^2-4(18)=0

4v^4k^2=72

k^2=18/v^4

k=3√2/v^2

Similar questions