Question

Find the value (s) of k,if the quadratic equation 3xsquare-k√3xplus4=0 has equal roots

Answer 1

Answer:

k=4

Step-by-step explanation:

3x²-k√3x+4=0

alpha=beta

Now alpha+beta=k√3/3

2alpha=k√3/3

alpha =k√3/6

alpha * beta =4/3

(alpha)²=4/3

(k√3/6)²=4/3

3k²/36=4/3

k²=4*36/3*3

k²=4*4

Hence k=4

Hope It Helps

Answer 2

$3x {}^{2} - k \sqrt{3} x + 4 = 0$
from
${a}^{2} + bx + c = 0$
so
a=3 ,b= - k root3 ,c=4

${b}^{2} = 4ac$
$3k {}^{2} = 4 \times 3 \times 4$
$k = \sqrt{48 \div 3}$
$k = 4$









Radhe Radhe