Find the value(s) of m for which the quadratic equation mx²
– mx+4 = 0 has
equal roots.
Answers
Answered by
0
Answer:
mx(6x+10)+25=0
6mx2+10mx+25=0
Roots are equal so D=0
{10m}2−4.25(6m)=0
m2−6m=0
m(m−6)=0
∴m=6
Similar questions