Harish and peter working separately can paint a building in 18 days and 24 days respectively. If they work for a day alternately, harish beginning, in how many days, the painting work will be completed
Answers
Answer:
A can do piece of work in 18 days
One day work of A is 1/18
B can do the piece of work in 24 days
One day work of B =1/24
So,
(A+B)'s one day work=
= > \frac{1}{18} + \frac{1}{24}=>
18
1
+
24
1
\begin{lgathered}= > \frac{4 + 3}{72} \\ = > \frac{7}{72}\end{lgathered}
=>
72
4+3
=>
72
7
They worked for 8 days
So,
Worked complete =
\begin{lgathered}= > \frac{7}{72} \times 8 \\ = > \frac{7}{9}\end{lgathered}
=>
72
7
×8
=>
9
7
Now,
Remain work=
\begin{lgathered}= > 1 - \frac{7}{9} \\ = > \frac{2}{9}\end{lgathered}
=>1−
9
7
=>
9
2
So,
the remain work done by B in
\begin{lgathered}= > \frac{2}{9} \div \frac{1}{24} \\ = > \frac{2}{9} \times \frac{24}{1} \\ = > \frac{16}{3}\end{lgathered}
=>
9
2
÷
24
1
=>
9
2
×
1
24
=>
3
16
So,the remain work done by B in 16/3 days