Question

Find the value(s) of x, if the distance between the points A(0, 0) and
B(x,- 4) is 5 units.
27​

Answer 1

Answer:

AB=

$\sqrt{(x2 - x1) {2} + ( {y2 - y1)}^{2} }$

5= [(x-0)^2 + (-4-0)^2]^1/2

5^2= x^2 + 16

25= x^2 + 16

x^2 = 9

x=3

Step-by-step explanation:

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