Question

find the value

$1 \div \sqrt{32} - \sqrt{18}$
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Answer 1

Answer:

Step-by-step explanation:

Given that,

1 ÷ √32 - √18

= 1 ÷ 4√2 - 3√2 [∵ √32 = √16 × 2 = 4√2 ; √18 = √9× 2 = 3√2 ]

= 1 ÷ √2

= √2 / 2 [∵ 1÷√2 =Rationalising the denominator ⇒1/√2 × (√2/√2) = √2 / ( √2)²=√2/2 ]

= √2 / 2 is the answer.