Math, asked by poojakumaresh26, 1 year ago

find the value... trigonometry ques

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Answered by harshraj2717

he is your answer.....
Mark it as brainliest....

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poojakumaresh26: how does 3/√3 divide can u please explain

harshraj2717: I have rationalised it

poojakumaresh26: Is it by √3*√3 /√3 thn by canceling we get√3

harshraj2717: no...its 3 / ✓3 * ✓3 / ✓3 = 3✓3 / 3 and then by cancelling 3 we get ✓3

poojakumaresh26: ohk

Vaiarathe: Your way of saying: 3/√3 = (√3 × √3) / √3 = √3 ... By cancelling, we get √3. This is correct. No need to rationalize any further

Vaiarathe: Your way is correct@pooja

Vaiarathe: Actually, both way are correct. Pooja's way is faster

poojakumaresh26: thnx for the clarification

Answered by TPS

Here, you have divided both sides by √3. But the mistake is you forgot to divide 3 by √3.

$\sqrt{3} \tan(2x) - 3 = 0$

Now add 3 to both sides,
$\sqrt{3} \tan(2x) - 3 + 3 = 0 + 3 \\ \\ \sqrt{3} \tan(2x) = 3$

Now divide both sides by √3
$\frac{ \sqrt{3} \tan(2x)}{ \sqrt{3} } = \frac{3}{ \sqrt{3} } \\ \\ \tan(2x) = \sqrt{3}$

Now compare the angle,
$\tan(2x) = \tan(60)$

$thus \: \: 2x = 60 \\ \\ x = 30$

thus the angle is 30°

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