Question

Find the value x and find out all missing angles in the following parallelogram

Answer 1

Answer:

Hope my answer helps you mate :-)

Step-by-step explanation:

First in Triangle QBC

By angle sum property of triangle

3x+7x+30=180

10x=180-30

x=150/10=15

So angle QCB=15×7=105degree

Now Similiarly Angle QAB = 105 degree as Opposite angles of parallelogram are equal

And Angle QBA=AQB. (alternative angles)

So CBA=45+30=75

Again as opposite angles of parallelogram are given equal

So CBA=AQC=75

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Answer 2

Answer:

X = 15

angle Q = angle B = 75°

angle A = angle C =105°

Step-by-step explanation:

30° + 3x + 7x = 180°

30° + 10x = 180°

10x = 180°-30°

10x = 150°

X = 150÷10

X = 15°

so, angle

B = 3*15 = 45°

C = 7*15 = 105°

∆QAB = ∆QCB

angle A = angle C = 105°

angle Q= 30+45 = 75°

angle B = 45+30= 75°