Question

find the value
x and y if
x + 4iy = ix + y+ 3​

Answer 1

To find : Values of X and Y for the expression,  

x + 4iy = ix + y+ 3​

Explanation:

x + 4iy = ix + y+ 3​

Moving RHS to LHS,

⇒ x - y + 4iy - ix = 3

⇒ x - y + i (4y -x) = 3

Expanding RHS,

3 + 0i

⇒ x - y + i (4y -x) = 3 + 0i

Equating real and imaginary parts, we get,

x - y = 3 .... (1)

4y -x = 0 ....(2)

⇒ 4y = x

Equating in (1)

4y - y = 3

3y = 3

y = 1

Equating in (2)

4(1) - x = 0

x = 4

The values are x = 4 and y = 1.

Answer 2

Answer:

x=4: y=1

Step-by-step explanation:

x + 4yi = ix + y + 3

=x-y+4yi-ix=3

=x-y+i(4y-x)=3

We can write 3 as 3+0i

=x-y+i(4y-x)=3+0i

Equating the real and imaginary parts...

x-y=3

4y-x=0

4y=x

=4y-y=3

y=1

x=4