Question

find the valueof K
4a²x²-4abx+k=0​

Answer 1

Answer:

Step-by-step explanation:

4a^2x^2-4abx+k

b^2-4ac=0

(-4ab)^2-4(4a^2)k=0

-16a^2b^2+16a^2k=0

-16a(b^2+k)=0

b^2+k=0

k=-b^2