Question

Find the values of a and b for which x = 3/4and x =-2 are the roots
of the equation ax^2 + bx - 6 = 0.​

Answer 1

Answer:

Step-by-step explanation:

x=3/4                                                  x=-2

a*9/16+3b/4-6 = 0                             4a-2b-6 = 0

9a/16 +3b/4 = 6                                 4a-2b = 6

1. 9a+12b = 96                                 2.24a-12b = 36

adding 1,2

33a = 132

a = 4                

putting a in 1                                    a = 4

36 + 12b = 96                                   b = 5

b = 5