find the values of a and b, if 2 and 3 are zeros of x3 +ax2+bx-30
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Step-by-step explanation:
Case-1:
If 2 is the zero of x³+ax²+bx-30=0
=>(2)³+a(2)²+b(2)-30=0
=>(4a+2b=22)÷2
=>(2a+b=11)×3
=>6a+3b=33---(1)
Case-2:
If 3 is the zero of x³+ax²+bx-30=0.
=>(3)³+a(3)²+b(3)-30=0
=>9a+3b=3----(2)
By elimination method:
6a+3b-(9a+3b)=33-3
6a+3b-9a-3b=30
-3a=30
a=30/-3=-10.-------(3)
(3) in (2)
9a+3b=3
9(-10)+3b=3
-90+3b=3
3b=3+90=93
b=93/3=31.
The values of a and b are -10 and 31.
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