Question

Find the values of a and b if
3 + √2 / 3- √2 = a+b √2.
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Answer 1

LHS

3+√2/3-V2

= (3+√2)^2 /{3-√2}{3+√2}

= (9+2+6√2)/9-4

= (11+6√2)/5

= 11/5  +   6√2/5

On comparing LHS AND RHS  we get,,

a=11/5

and,

b= 6/5

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