water flows through a pipe of internal diameter 7 cm at the rate of 15 km/h into a rectangular tank 50m long and 44m wide. in what time the level in the tank will rise by 21 cm?
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Step-by-step explanation:
here
D= 7cm
r= .07m/2=0.035m
rate of water flowing= 15km/h = 15×1000m/60min
= 1500m/6min= 250m/min
Let this be the height of the pipe as water flows= this length every min.
Vol of the pipe= πr²(h)
= 22/7×0.035m×0.035m× 250m/min
=22×0.005m×.35m×25m/min
volume of a cuboid= l×b×h= 50m×44m× .21m= 10.5m²×44m= 462.0m³
Time taken = 462m³/22×0.005m×.35m×25m/min
= 462×1000×100 min/ 22×5×35×25
= 42×1000×4min/2×5×35
= 21×1000×4min/35×5
= 21×200×4min/35 = 21× 40×4min/7= 3×40×4 min
= 480min
or 8hrs
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