Find the values of a and b if 3 / ( √3-√2) = a√3 -b√2
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3/ (√3-√2)= a√3-b√2
LHS, rationalising
3/(√3-√2) * (√3+√2)/(√3+√2)
3√3+3√2/(√3)²-(√2)² [a²-b²=(a+b)(a-b)]
3√3+3√2/3-2
3√3+3√2/1
On comparing with RHS, we get
a=3 and b= -3
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