Math, asked by contactaamina, 6 months ago

Find the values of a and b if 3 / ( √3-√2) = a√3 -b√2
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Answers

Answered by himmatr12
0

Answer:

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Step-by-step explanation:

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Answered by pradnya250604
0

Answer:

3/ (√3-√2)= a√3-b√2

LHS, rationalising

3/(√3-√2) * (√3+√2)/(√3+√2)

3√3+3√2/(√3)²-(√2)²                         [a²-b²=(a+b)(a-b)]

3√3+3√2/3-2

3√3+3√2/1

On comparing with RHS, we get

a=3 and b= -3

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