Math, asked by keshavbhardwaj33, 9 months ago

Find the values of a and b
if (7+3√5/3+√5) + (7-3√5/3-√5) = a+√5b​

Answers

Answered by shivamtiwarihom
2

Answer:

14=a and 0=b

Step-by-step explanation:

7+3 √5/3+ √5+7-3 √5/3- √5=a+ √5b

+3 √5/3 cancelled with -3 √5/3.

7+ √5+7- √5=a+ √5b

then  +√5 cancelled with - √5

7+7=a+ √5b

14=a+ √5b

a=14 and b=0

because when b is zero eq. comes a+ √5*0.so B=0.


keshavbhardwaj33: please show step by step
shivamtiwarihom: step by step
keshavbhardwaj33: yes
Answered by PiyushDash
2

Answer:

I hope this will help you.

Attachments:

keshavbhardwaj33: I think it should be 12/4
PiyushDash: You got it
PiyushDash: Thanks
PiyushDash: Is a = 3 or 14
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