Find the values of a and b
if (7+3√5/3+√5) + (7-3√5/3-√5) = a+√5b
Answers
Answered by
2
Answer:
14=a and 0=b
Step-by-step explanation:
7+3 √5/3+ √5+7-3 √5/3- √5=a+ √5b
+3 √5/3 cancelled with -3 √5/3.
7+ √5+7- √5=a+ √5b
then +√5 cancelled with - √5
7+7=a+ √5b
14=a+ √5b
a=14 and b=0
because when b is zero eq. comes a+ √5*0.so B=0.
keshavbhardwaj33:
please show step by step
Answered by
2
Answer:
I hope this will help you.
Attachments:
Similar questions