find the values of a and b so that the polynomial xcube + 10xsquare + ax + b is exactly divisible by x - 1 as well as x - 2 ... can anyone pls answer me this question
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1
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can you write it clearly...
Answered by
0
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Hello Mate!
Factor theorum states that p( x ) = 0
x = 1, 2
p( x ) = x^3 -10x^2+ax+ b
0 = 1 - 10 + a + b
0 = - 9 + a + b ------(1)
0 = 2^3 - 10(2)^2 + a(2) + b
0 = 8 - 40 + 2a + b
0 = - 32 + 2a + b ------(2)
(1) - (2)
-9 + a + b
-( - 32 + 2a - b )
23 - a = 0
a = 23
keeping value of a in eq. 1
0 = - 9 + 23 + b
-14 = b
Hope it helps☺!✌
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