Question

find the values of a and b so that x⁴+x³+8x²+ax+b is divisible by x²+1

Answer 1

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Answer 2

Answer:

a = 1 & b = 7

Step-by-step explanation:

$x^{4} + x^{3} + 8x^{2} +ax+b$ / $x^{2} +1$ = x(a-1) + b-7

so,r = 0; i.e. x(a-1) + b-7=0

• a-1 = 0

        a = 1

• b-7 = 0

        b = 7