. Find the values of a, b and c, such that the numbers a, 10, b, c, 31 are in A.P.
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Step-by-step explanation:
mind the cropping,otherwise everything is good
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Answer:
now the difference is
10-a=b-10=31-c=c-b
- so....a+b=20
- so...b+c=41
- so....c-a=21
- so....c-b+a=10
solving the equations.
21+2a-b=10
2a-b=-11
so...3a=9=>a=3
the series is .....3,10,17,24,31
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