Question

Find the values of alpha for which distance between the points P (2, -3 ) and Q ( alpha, 5) is 10​

Answer 1

wyh-qcwa-qda

Answer:

jddjkdrr!fvkf

Answer 2

Step-by-step explanation:

instead of alpha i am using 'x'

by distance formula PQ =

√((x-2)^2+(5+3)^2)=10

squaring both sides and simplfying

(x-2)^2+64=100

(x-2)^2=36

x-2=+-(6)

square root on both sides

x-2=6. x-2= -6

x=8. x= -4