Question

find the values of 'b' in:
3-√5÷3+2√5 = a√5-19/11 b​​

Answer 1

Answer:

$b = ( \sqrt{5} (a + \frac{7}{3} ) - 3) \frac{11}{19}$

Step-by-step explanation:

$3 - \frac{ \sqrt{5} }{3} + 2 \sqrt{5} = a \sqrt{5} - \frac{19}{11} b$

$3 - \sqrt{5} ( \frac{1}{3} + 2) = a \sqrt{5} - \frac{19}{11} b$

$3 - \frac{7 \sqrt{5} }{3} = a \sqrt{5} - \frac{19}{11} b$

$3 + \frac{19}{11} b = a \sqrt{5} + \frac{7 \sqrt{5} }{3}$

$\frac{19}{11} b = \sqrt{5} (a + \frac{7}{3} ) - 3$

$b = ( \sqrt{5} (a + \frac{7}{3} ) - 3) \frac{11}{19}$