Math, asked by XxcopycatxX, 6 hours ago

Find the values of each of the following:

(i) (27) ^-2/3
(ii) (343) ^-2/3
(iii) (512)^-2/9

Answers

Answered by vivekkumarpatar2007
1

Answer 1(i) 26 = 2 × 2 × 2 × 2 × 2 × 2 = 64

(i) 26 = 2 × 2 × 2 × 2 × 2 × 2 = 64(ii) 93 = 9 × 9 × 9 = 729

(i) 26 = 2 × 2 × 2 × 2 × 2 × 2 = 64(ii) 93 = 9 × 9 × 9 = 729(iii) 112 = 11 × 11 = 121

(i) 26 = 2 × 2 × 2 × 2 × 2 × 2 = 64(ii) 93 = 9 × 9 × 9 = 729(iii) 112 = 11 × 11 = 121(iv)54 = 5 × 5 × 5 × 5 = 625

Answer 2(i) 6 × 6 × 6 × 6 = 64

(i) 6 × 6 × 6 × 6 = 64(ii) t × t= t2

(i) 6 × 6 × 6 × 6 = 64(ii) t × t= t2(iii) b × b × b × b = b4

(i) 6 × 6 × 6 × 6 = 64(ii) t × t= t2(iii) b × b × b × b = b4(iv) 5 × 5 × 7 × 7 × 7 = 52 × 73

(i) 6 × 6 × 6 × 6 = 64(ii) t × t= t2(iii) b × b × b × b = b4(iv) 5 × 5 × 7 × 7 × 7 = 52 × 73(v) 2 × 2 × a × a = 22 × a2

(i) 6 × 6 × 6 × 6 = 64(ii) t × t= t2(iii) b × b × b × b = b4(iv) 5 × 5 × 7 × 7 × 7 = 52 × 73(v) 2 × 2 × a × a = 22 × a2(vi) a × a × a × c × c × c × c × d = a3 c4 d

Answer 3512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 29

512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 29(ii) 343 = 7 × 7 × 7 = 73

512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 29(ii) 343 = 7 × 7 × 7 = 73(iii) 729 = 3 × 3 × 3 × 3 × 3 × 3 = 36

512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 29(ii) 343 = 7 × 7 × 7 = 73(iii) 729 = 3 × 3 × 3 × 3 × 3 × 3 = 36(iv) 3125 = 5 × 5 × 5 × 5 × 5 = 55

Answered by gabby73
1

Step-by-step explanation:

1.(3^3)^-2/3 = 3^-2 = 1/3^2=1/9

2.(7^3)^-2/3 = 7^-2 = 1/7^2=1/49. 3(2^9)^-2/9 = 2^-2 = 1/2^2=1/4

Similar questions