find the values of k for each of the following quadratic equations so that they have two equal roots
I NEED 2 QUESTION
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eq is 2x²+kx+3=0
let its roots are ø and ê
standard eq is ax²+bx+c=0
then ø+ê= -b/a and ø.ê=c/a
as equal roots so ø =ê
2ø= -k/2 and ø² = 3/2
so ø=√(3/2)
k= -4×√(3/2)
k = -2√2×√3
finally k = -2√6
now iind questions
eq.is kx(x-2)+6=0
means kx²- 2kx + 6 =0
here a = k n b = -2k n c= 6
here 2ø = -(-2k)/k
and ø²= 6/k
from ist ø= 1
means 6/k=1
k=6
If this helps u mark it as brainliest.
let its roots are ø and ê
standard eq is ax²+bx+c=0
then ø+ê= -b/a and ø.ê=c/a
as equal roots so ø =ê
2ø= -k/2 and ø² = 3/2
so ø=√(3/2)
k= -4×√(3/2)
k = -2√2×√3
finally k = -2√6
now iind questions
eq.is kx(x-2)+6=0
means kx²- 2kx + 6 =0
here a = k n b = -2k n c= 6
here 2ø = -(-2k)/k
and ø²= 6/k
from ist ø= 1
means 6/k=1
k=6
If this helps u mark it as brainliest.
neha89:
thanks
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