Math, asked by aakashdeep9099, 6 months ago

Find the values of k for each of the quadratic equations, so that they have two real equal roots:

x

2

- 4kx +k = 0.​

Answers

Answered by arnavshar17
0

Answer:

ok I got your question the answer is k =  0 and 1/4

Step-by-step explanation:

in order for the equation to have equal roots the D or discriminant should be equal to zero

therefore b^2 -4ac should be equal to 0

putting the values in:

16k^2 -4k=0

4k^2-k = 0 (taking 4 as common and transporting to r.h.s)

k(4k-1) = 0 (k as common)

therefore k is either 0 or 1/4

hope this answer helped have a great day!!

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