find the values of k for quadratic eqution 2x^2 +kx +3 so that they have two equal roots
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Answered by
1
b^-4ac=k^2-4*2*3=0
k^2=24
k=+ or - 2√6
k^2=24
k=+ or - 2√6
ElsAnna:
as the root are equal the discriminant shoul be equal to 0
therfore b^2-4ac=0
Answered by
0
To have two equal roots,
b^2-4ac=0
K^2 -4(2)(3)=0
K^2=24
K^2= √24
=2 √6
Hope it helps!!!
b^2-4ac=0
K^2 -4(2)(3)=0
K^2=24
K^2= √24
=2 √6
Hope it helps!!!
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