Question

find the values of k for the quadratic equation k(x) (x-2)+6=0,so that they are two equal roota​

Answer 1

Kx^2-2kx +6=0

Equal roots implies that D=0

This implies that b^2-4ac=0

(-2k)^2 -24k=0

4k^2-24k=0

4k(k-6)=0

4k=0

This implies that k=0

And k-6=0

This implies that k=6

So,k=0,6