find the values of k for the quadratic equation kx(x-2)+6=0,so that it has two equal roots
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Answered by
10
kx (x-2)+6=0
kx^2-2kx+6=0
a=k b=2k c=6
D=b^2-4ac
D=(2k)^2-4 (k)(6)
D=4k^2-24k
Therefore
4k(k-6)=0
k-6=0
k=6
or
k=0
kx^2-2kx+6=0
a=k b=2k c=6
D=b^2-4ac
D=(2k)^2-4 (k)(6)
D=4k^2-24k
Therefore
4k(k-6)=0
k-6=0
k=6
or
k=0
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7
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