Question

find the values of k for which 2x^2+kx+3=0 has two equal roots​

Answer 1

Answer:

2x^2-x+2=0

Step-by-step explanation:

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Answer 2

Required Answer :-

• k = ± 2√6

To find:-

• the value of k

Given quadratic equation: 2x² + kx + 3 = 0

Thus,

• Discriminant: D = b² - 4ac = 0

• Comparing 2x² + kx + 3 = 0 with the equation: ax² + bx + c = 0; we get,
• a = 2, b = k and c = 3

• Thus, D = (k)² - 4 ×(2) × (3) = 0

• => k² - 24 = 0

• k² = 24

• k = √24

• k = +2√6 or -2√6

Thus, the value of k is ± 2√6.

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