CBSE BOARD X, asked by parthu6809, 1 year ago

find the values of K for which the equation9x²+2Kx+1=0 has real roots

Answers

Answered by brainly218
6
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a = 9 , b = 2k, c = 1
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D = b2-4ac
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0 = (2k)2-4*9*1
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0 = 4k2-36
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36 = 4k2
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36/4 = k2
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k = √ 9 = 3

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