Question

find the values of K for which the given simultaneous equation having Infinity many solution K X + 4 Y = 10 and 3 X + 2 Y = 5​

Answer 1

Answer:

condition: a1/a2 is equal to b1/b2..

Step-by-step explanation:

Here,a1=K

a2=3

b1=4

b2=2

substitute the values in the formula:

a1/a2=b1/b2

K/3=4/2

K/3=2/1

by cross multiplication,

2×3=K

k=6

Hence ,the equation has many solutions...

Answer 2

Answer:

k = 6

3X + 2Y = 5

X = 1 and Y = 1 then 5 is possible

k(1) + 4 (1) = 10

k + 4 = 10

k = 10-4

k=6