find the values of k for which the pair of linear equations kx+3y=k-3 and 12x+ky =k
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here is your answer by Sujeet
a1/a2=b1/b2
k/12=3/k
k²=36
k=√36
k±6
that's all
a1/a2=b1/b2
k/12=3/k
k²=36
k=√36
k±6
that's all
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