Question

Find the values of k for which the polynomial kx²+x+k has equal roots​

Answer 1

If a quadratic equation has equal roots, then the determinant,

${b}^{2} - 4ac \: = 0$

where, a = coefficient of

${x}^{2}$

b = coefficient of

$x$

and c is the constant part.

Here, a = k, b = 1 and c = k

So,

$1 - 4 {k}^{2} = 0$

$4 {k}^{2} = 1$

$k = \sqrt{ \frac{1}{4} }$

$k = \frac{1}{2}$

or

$k = - \frac{1}{2}$

[THANK YOU]