Question

- Find the values of k for which the quadratic equation k^2x^2 -2(k-1)x + 4 = 0 has real and equal
roots.​

Answer 1

Step-by-step explanation:

the given qudratic equation is;

k^2x^2-2(k-1)x+4=0

for real and equal roots,

=> D=0

=> [-2(k-1)]^2 -4•k^2•4 =0

=> 4(k^2+1-2k)-4•k^2•4=0

=> k^2+1-2k-4k^2=0

=> 3k^2+2k-1=0

=> (k+1)(3k-1)=0

=> k=1/3 or -1

I hope it would help you out

thank you