Find the values of k for which the quadratic equation (k + 4) x2 + (k + 1) x + 1 = 0 has equal roots.
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D=0
b×b -4×ac
k×k+16+8k-4k-16 = 0
k2+4k =0
k(k+4) = 0
k=-4 or 0
b×b -4×ac
k×k+16+8k-4k-16 = 0
k2+4k =0
k(k+4) = 0
k=-4 or 0
Answered by
2
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