Question

Find the values of k for which the quadratic equation (k + 4) x2 + (k + 1) x + 1 = 0 has equal roots.

Answer 1

D=0
b×b -4×ac
k×k+16+8k-4k-16 = 0
k2+4k =0
k(k+4) = 0
k=-4 or 0

Answer 2

$(k + 4) x 2 + (k + 1)x + 1 = 0$