Math, asked by kurosaki006, 1 month ago

find the values of k for which the roots of x²+2kx+9=0 are real and equal
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Answers

Answered by vinayvallapudasu72
0

Answer:

b^2-4ac/2a

x^2+2kx+9=0

a=1, b=2k, c=9

2k^2-4×1×9/2×1

4k^2-36/2

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