Question

Find the values of k if first three terms of an AP are respectively 3k-1,3k+5,5k+1

Answer 1

Answer:

$2(3k + 5) = 3k - 1 + 5k + 1 \\ \\ 6k + 10 = 8k \\ \\ 2k = 10 \\ \\ k = 5$