Question

find the values of K in the following polynomial for which the indicated values of x are their zeros kx square—x—2. (x=2/3)

Answer 1

since x=2/3
putting value of x in equation
kx²-x-2=0
k(2/3)²-2/3-2=0
4k/9-2/3-2=0
4k/9= 2+2/3
4k/9= (6+2)/3
4k/9= 8/3
4k= 8/3×9
4k= 24
k= 24/4
k= 6
................hope u got ur answer

Answer 2

Answer:

since x=2/3

putting value of x in equation

kx²-x-2=0

k(2/3)²-2/3-2=0

4k/9-2/3-2=0

4k/9= 2+2/3

4k/9= (6+2)/3

4k/9= 8/3

4k= 8/3×9

4k= 24

k= 24/4

k= 6