Question

Find the values of k so that the quadratic equation
(4 – K)x2 + 2(k + 2)x + (8k + 1) = 0 has equal roots.​

Answer 1

Answer:

it is the correct answer.

Step-by-step explanation:

(4−k)x

2

+2(k+2)x+(8k+1)=0 for equal roots, D=0

a=(4−k),b=2k+4,c=8k+1, D=b

2

−4ac

D=(2k+4)

2

−4(8k+1)(4−k)

O=4k

2

+16+16k−4(32k−8k

2

+4−k)

O=4k

2

+16k+16−128k+32k

2

−16+4k

O=36k

2

−108k

O=k(36k−108)

∴k=0,k=3

36k=108

k=3.

I hope it will help you.

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