Math, asked by selena10, 1 year ago

find the values of k so that (x+1) is a factor of k^2.x ^2-2kx-3.

Answers

Answered by mysticd
37
Hi ,

Let p( x ) = k² x² - 2kx - 3

If ( x + 1 ) is a factor p( x ) then

Remainder p ( - 1 ) = 0

k² ( - 1 )² - 2 k ( - 1 ) - 3 = 0

k² + 2k - 3 = 0

k² - k + 3k - 3 = 0

k ( k - 1 ) + 3 ( k - 1 ) = 0

( k - 1 ) ( k + 3 ) = 0

k - 1 = 0 or k + 3 = 0

k = 1 or k = - 3

I hope this helps you.

:)
Answered by mkguptalwarp8uuup
14

Answer:

Step-by-step explanation:Let p( x ) = k² x² - 2kx - 3

If ( x + 1 ) is a factor p( x ) then

Remainder p ( - 1 ) = 0

k² ( - 1 )² - 2 k ( - 1 ) - 3 = 0

k² + 2k - 3 = 0

k² - k + 3k - 3 = 0

k ( k - 1 ) + 3 ( k - 1 ) = 0

( k - 1 ) ( k + 3 ) = 0

k - 1 = 0 or k + 3 = 0

k = 1 or k = - 3

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