find the values of k so that (x+1) is a factor of k^2.x ^2-2kx-3.
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Answered by
37
Hi ,
Let p( x ) = k² x² - 2kx - 3
If ( x + 1 ) is a factor p( x ) then
Remainder p ( - 1 ) = 0
k² ( - 1 )² - 2 k ( - 1 ) - 3 = 0
k² + 2k - 3 = 0
k² - k + 3k - 3 = 0
k ( k - 1 ) + 3 ( k - 1 ) = 0
( k - 1 ) ( k + 3 ) = 0
k - 1 = 0 or k + 3 = 0
k = 1 or k = - 3
I hope this helps you.
:)
Let p( x ) = k² x² - 2kx - 3
If ( x + 1 ) is a factor p( x ) then
Remainder p ( - 1 ) = 0
k² ( - 1 )² - 2 k ( - 1 ) - 3 = 0
k² + 2k - 3 = 0
k² - k + 3k - 3 = 0
k ( k - 1 ) + 3 ( k - 1 ) = 0
( k - 1 ) ( k + 3 ) = 0
k - 1 = 0 or k + 3 = 0
k = 1 or k = - 3
I hope this helps you.
:)
Answered by
14
Answer:
Step-by-step explanation:Let p( x ) = k² x² - 2kx - 3
If ( x + 1 ) is a factor p( x ) then
Remainder p ( - 1 ) = 0
k² ( - 1 )² - 2 k ( - 1 ) - 3 = 0
k² + 2k - 3 = 0
k² - k + 3k - 3 = 0
k ( k - 1 ) + 3 ( k - 1 ) = 0
( k - 1 ) ( k + 3 ) = 0
k - 1 = 0 or k + 3 = 0
k = 1 or k = - 3
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