Math, asked by sivachidambaramthang, 1 year ago

find the values of K such that the equation Mod of x square - 5 mod x + 6 is equal to K is satisfied by six distinct values of x

Answers

Answered by rajivrtp
2

Step-by-step explanation:

Ix²I- 5Ix+6I = K

if X>0

x²- 5x+6=k..............,...(1)

if X<0

case 1:-.

- (x²) I+ I( 5x+6) I= k

-x²+ 5x+6 = k ..........................(2)

case2:-

Ix²I + I -( 5x+6)I= k

x²+5x+6= k...............,....(3)

from (1) and (2)

x²-5x= =0

x= 0 , 5

from(2) and (3)

x= 0

from(1) and (3)

x= 0

substituting the value of x=0 in(1)

k= 6

if X= 5 then all the eqn not satisfied for k≠6

therefore k= 6

Answered by temporarygirl
0

Hola mate

Here is your answer -

Ix²I- 5Ix+6I = K

if X>0

x²- 5x+6=k..............,...(1)

if X<0

case 1:-.

- (x²) I+ I( 5x+6) I= k

-x²+ 5x+6 = k ..........................(2)

case2:-

Ix²I + I -( 5x+6)I= k

x²+5x+6= k...............,....(3)

from (1) and (2)

x²-5x= =0

x= 0 , 5

from(2) and (3)

x= 0

from(1) and (3)

x= 0

substituting the value of x=0 in(1)

k= 6  

if X= 5 then all the eqn not satisfied for k≠6

therefore k= 6

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