Find the values of k such that the quadratic equation x square - 2kx + (7k-12) = 0 has equal roots.
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HERE IS YOUR ANSWER...
Since, it has equal roots.
Therefore, D = 0
=> b^2 - 4ac = 0
=> (-2k)^2 - 4 × 1 × (7k - 12) = 0
=> 4k^2 - 28k + 48 = 0
=> 4 (k^2 - 7k + 12) = 0
=> k^2 - 4k - 3k + 12 = 0
=> k (k - 4) - 3 (k - 4) = 0
=> (k - 4)(k - 3) = 0
=> k = 4 and 3.
# GUDIYA...
HOPE IT HELPS..!!!☺☺☺
HERE IS YOUR ANSWER...
Since, it has equal roots.
Therefore, D = 0
=> b^2 - 4ac = 0
=> (-2k)^2 - 4 × 1 × (7k - 12) = 0
=> 4k^2 - 28k + 48 = 0
=> 4 (k^2 - 7k + 12) = 0
=> k^2 - 4k - 3k + 12 = 0
=> k (k - 4) - 3 (k - 4) = 0
=> (k - 4)(k - 3) = 0
=> k = 4 and 3.
# GUDIYA...
HOPE IT HELPS..!!!☺☺☺
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