Find the values of m and n if y4 + my3 + 2y2 - 3y + n is divisible by y2-1
URGENT!! tom maths xam!!!
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Answer:
n = -3 , m = 3
Step-by-step explanation:
p(y) = y^4 + my³ + 2y² - 3y + n = 0
y²-1 = 0 , y = ±1
p(1) = 1 + m + 2 - 3 + n = 0 , m+n = 0
p(-1) = 1 - m + 2 + 3+ n = 0 , -m+n = -6 , n = -3 , m = 3
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