Find the values of m' for which 2 + 3xy +x+ my-m has two linear factors in and y,
with integer coefficients.
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Answer:
Step-by-step explanation:
Let x
2
+3xy+x+my−m=(ax+by+c)(ex+fy+g)
∴x
2
+3xy+x+my−m=(ax+by+c)(ex+g)
or x
2
+3xy+x+my−m=aex
2
+bexy+cex+agx+bgy+cg
Equating the coefficients :
ae=1...(1) be=3...(2) ce+ag=1...(3)
bg=m...(4) cg=−m...(5)
Then. from eq (1)(2) a=e=1,b=3
Putting in eq (3):e+g=1...(6)
Now,
c
b
=−1 or c=−b,c=−3
From eg (6), −3+9=1 or g=4
Putting in (5) : −m=−3×4⇒m=12
solution
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Step-by-step explanation:
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