Find the values of m for which the equation 3x² + 6x + m= 0 has two distinct real roots.
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Answered by
13
Given equation is
3x² + 6x + m= 0
On Comparing With ax²+ bx+c= 0
a= 3, b= 6 , c= m
Discriminant (D) = b² - 4ac
D= 6²- 4× 3× m
D= 36 -12m
D= 12(3-m)
since ,roots of given equation are distinct real roots.
D> 0 ( two real & distinct roots)
36 -12m > 0
36 > 12m
12m < 36
m < 36/12
m < 3
Hence, the given Equation will have distinct roots , if m< 3.
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Hope this will help you....
3x² + 6x + m= 0
On Comparing With ax²+ bx+c= 0
a= 3, b= 6 , c= m
Discriminant (D) = b² - 4ac
D= 6²- 4× 3× m
D= 36 -12m
D= 12(3-m)
since ,roots of given equation are distinct real roots.
D> 0 ( two real & distinct roots)
36 -12m > 0
36 > 12m
12m < 36
m < 36/12
m < 3
Hence, the given Equation will have distinct roots , if m< 3.
==================================================================================
Hope this will help you....
24032002:
Value of my can be equal to 3 because condition for reliability roots is D=0
here condition is given real distinct roots
D= 0 when roots are real & equal
In real & distinct roots D>0
yes
thanks Nikita
it was some misunderstanding in reading the question
Answered by
9
Having a real and distinct roots means D>0
Therefore D=b²-4ac>0
Here a=3, b=6, and c=m
Therefore D=6²-4(3)(m)
=36-12m=0
-12m=-36
m=36/12
m=3
Hence value of m > 3
Hope it helps you
All the best
--Mariya
Therefore D=b²-4ac>0
Here a=3, b=6, and c=m
Therefore D=6²-4(3)(m)
=36-12m=0
-12m=-36
m=36/12
m=3
Hence value of m > 3
Hope it helps you
All the best
--Mariya
correct ur answer
This is wrong answer
Ur answer is wrong.. correct it...
thank you for correcting me
I didn't read the answer properly
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