Question

find the values of P AND Q
3+ROOT7 ÷ 3- root 7 =P+Qroot 7​

Answer 1

Here's your answer!!!

Answer 2

Answer:

$\frac{3 + \sqrt{7} }{ 3 - \sqrt{ 7} } = p + q \sqrt{7} \\ rationalise \: the \: denominator \: \\ \frac{3 + \sqrt{7} }{3 - \sqrt{7} } \times \frac{3 + \sqrt{7} }{3 + \sqrt{7} } = p + q \sqrt{7} \\ \frac{9 + 6 \sqrt{7 } + 7 }{9 - 7} = p + q \sqrt{7} \\ \frac{16 + 6 \sqrt{7} }{2} = p + q \sqrt{7} \\ 8 + 3 \sqrt{7} = p + q \sqrt{7} \\ equating \: both \: side \:p = 8 \: \: \: \: q = 3$