Question

find the values of P and Q for which the following of equation has number of solution 2 X + 3 Y is equals to 7. (p+q) x+(2p-a)y=21 ​

Answer 1

Answer:

Hey there!

Step-by-step explanation:

2x + 3Y =7, multiply the eqn by 3 => 6x+9y = 21.

Therefore, compare the coefficients.

(p+q) = 6

(2p - a)= 9

therefore, p= (9+a)/2

q= (3-a)/2

Hope it helps!