Find the values of p and q so that 1 and -2 are the zeroes of the polynomial
〖f(x)=x〗^3+10x^2+px+q and then find the third zero.
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Step-by-step explanation:
Aloha !
Concept used here:-
Mathematical calculation
Given,.
f(x)=x³+10x²+px+q
And we have given 1 and -2 are zeros of the polynomial.
Replacing them in equation.
f(1)=(1)³+10(1)²+p(1)+q
f(1)=1+10+p+q
f(1)=p+q+11------>eq.1
And,.
f(-2)=(-2)³+10(-2)²+p(-2)+q
f(-2)=-8+40-2p+q
f(-2)=q-2p+32------>eq.2
Solving equations 1&2
3p=21
p=7
p+q=-11
7+q=-11
q=-18
Thank you
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