Question

Find the values of p and q so that 1 and −2 are the zeroes of the polynomial x3 + 10x2 + px + q and then find its third zero.

Answer 1

Heres your answer

p(1)=p(-2)

${1} + 10 + p + q = - 8 + 20 - 2p + q \\ \\ 11 + p + q = 12 - 2p + q \\ \\ 3p + 0 = 12 - 11 \\ \\ p = \frac{12}{3} = 4$
So the value of q=0 and p=4

and the third zero is 4..

Hope it Helps!!

Answer 2

Step-by-step explanation:

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