Question

Find the values of p for which the number 2p-1,3p+1,11 are in Ap

Answer 1

Answer: 2

Step-by-step explanation:

Given that a, b and c are in AP,

b - a = c - b

=> 2b = a + c

On substituting the values of a, b and c,

2(3p + 1) = (2p - 1) + 11

=> 6p + 2 = 2p - 1 + 11

=> 6p + 2 = 2p + 10

=> 6p - 2p = 10 - 2

=> 4p = 8

=> p = 8/4

=> p = 2

Therefore the value of p becomes 2

Hope it helps.....