Question

Find the values of p for which the quadratic equation
(p + 1) x2 – 6 (p+1)x + 3 (p + 9) = 0, p *-1 has equal roots. Hence, find
the roots of the equation
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Answer 1

Answer:

Given quadratic equation is= (p + 1)x² - 6(p + 1) x + 3 (p + 9) = 0. (p + 1)x² - 6(p + 1) x + 3 (p + 9) = 0. Hence , the roots are x =3, 3.